Area of Path and Verandah
Area of Path and Verandah
Area of Path & Verandah:
It is observed that in square or rectangular gardens or parks. Some space in the form of path is left inside or outside or in between as cross paths.
Illustration: A footpath of uniform width 5 m runs round the inside of a rectangular park 38 m long and 32 m wide. Find the area of the path.
Solution: Let ABCD be the rectangular park and PQRS be the internal boundaries of the path.
We have, Length AB= 38 m and Breadth BC= 32 m:
Thus, Area of rectangle ABCD = AB BC = 38 m
32 m = 1216
Now, Length PQ = 38 m - 5 m - 5 m = 28 m and Breadth QR = 32 m - 5 m - 5 m = 22m
Area of rectangle PQRS = PQ RS = 28 m
22 m = 616
Area of footpath = Area of rectangle ABCD - Area of rectangle PQRS = 1216 - 616=600
Thus, Area of footpath =600
The area of the crossroads = Area of the two colored rectangles - Area of the red colored rectangle at the centre.
We are subtracting the area of the rectangle because we are taking it into consideration two times.
A plot is 100 m long and 60 m broad.A path 5 m wide runs breadth wise across the ground in the middle.Find the area of path.
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| Right Option : B | |||
| View Explanation | |||
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A footpath of uniform width 7 m runs round the inside of a rectangular park 28 m long and 32 m wide. Find the area of the path. | |||
| Right Option : B | |||
| View Explanation | |||
A garden is 90 m long and 75 m board. A path 5 m wide is to be built outside all around it along its border. Find the area of the path?
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| Right Option : B | |||
| View Explanation | |||
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